0.8x^2+32X-960=0

Solution for 0.8x^2+32X-960=0 equation:

0.8x^2+32x-960=0

a = 0.8; b = 32; c = -960;
Δ = b2-4ac
Δ = 322-4·0.8·(-960)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-64}{2*0.8}=\frac{-96}{1.6}
=-60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+64}{2*0.8}=\frac{32}{1.6}
=20
$